What is complete autosomal dominant inheritance?
• In its simplest form, it involves 1 pair of genes with the
wild type gene "p" being recessive to the mutant gene "P"
in any combination. If the wild type/natural colour of a bird is purple and the
mutant form is yellow, the following will be true:
pp = Purple Bird
Pp = Pink Bird
PP = Pink Bird
• In the following example, one gene, we will call it "P", is responsible for
colour. The "P" gene comes in 2 forms: "P" and
"p". When the "P" gene is a capital "P", it is
responsible for the pink colour and classified as dominant. When the
"P" gene is a small "p", it is responsible for the
regular/wild type pink colour and is classified as recessive. The are always
2 copies of the "P" gene in each individual. If an individual is pp,
then it is purple/normal/wild type or is a homozygote (the pair of genes are
the same) for the purple gene. Purple is the recessive form. If an individual
is PP, then it is pink or in its dominant form. "PP" is a homozygote
for the pink gene. Most
autosomal dominant mutations are incomplete, but some are complete (as this one
is) meaning that the Split/heterzygote has the same phenotype (or appearance)
as the homozygous dominant form (PP). The phenotype for a Pp individual is
therefore pink like the PP individual . It is still a Split to purple, but it
appears pink.
"P" = pink gene
"p" = purple gene
PP = pink individual
Pp = pink individual
pp = purple individual
(1) Pink (PP) X Pink (PP) = All Pink (PP)
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(2) Purple (pp) X Purple (pp) = All Purple (pp)
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p |
p |
p |
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pp |
p |
pp |
pp |
(3) Pink (PP) X Purple (pp) = All Pink Split to Purple
(Pp)
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P |
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pp |
P |
Pp |
pp |
(4) Pink Split to Purple (Pp) X Pink Split to Purple
(Pp) = 25% Pink (PP), 50% Pink Split to Purple (Pp), & 25% Purple (pp)
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p |
P |
PP |
Pp |
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(5) Pink Split to Purple (Pp) X Pink (PP) = 50% Pink (PP) & 50% Pink Split to Purple (Pp)
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P |
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P |
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PP |
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P |
(6) Pink Split to Purple (Pp) X Purple (pp) = 50% Pink Split to Purple (Pp) & 50% Purple (pp)
P P p pp
